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x^2-25=3575
We move all terms to the left:
x^2-25-(3575)=0
We add all the numbers together, and all the variables
x^2-3600=0
a = 1; b = 0; c = -3600;
Δ = b2-4ac
Δ = 02-4·1·(-3600)
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{14400}=120$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-120}{2*1}=\frac{-120}{2} =-60 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+120}{2*1}=\frac{120}{2} =60 $
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